Answer:
The probability that the person you choose is either a woman or has never been married (or both) is therefore about 0.66
Step-by-step explanation:
Given Data:
Probability of choosing a women = P(W) = 0.52
Probability that chosen person has never married = P(M) = 0.26
Probability of choosing a women that has never married = P(W and M) = 0.11
We need to find the probability that the person you choose is either a woman or has never been married (or both). The addition rule of probabilities of two events is given as:
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) is the probability of occurrence of either A or B or both. P(A and B) is the probability of occurrence of A and B at the same time.
Re-writing the addition formula for given case, we get:
P(W or M) = P(W) + P(M) - P(W and M)
Substituting the given values results in:
P(W or M) = 0.52 + 0.26 - 0.11
P(W or M) = 0.67
Therefore, the probability that the person you choose is either a woman or has never been married (or both) is 0.67.
Note: There is either typo in given options or the questions. The question I found on Google has 0.25 as the probability that the person you choose has never married ( i.e. P(M) = 0.25 ).
So, in this case the correct answer would be option (b) 0.66
