3 years ago

What is the length of AB?

Mathematics

2 answers:

Vanyuwa [196]3 years ago

7 0

Answer:

6.6 is your answer.

Step-by-step explanation:

mart [117]3 years ago

6 0

Answer:

6.6

Step-by-step explanation:

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I need answer quickly

vagabundo [1.1K]

Answer:

4.47

Step-by-step explanation:

4^2+b^2=6^2

16+b^2=36

-16. -16

√b^2=√20

b=4.47

4 0

2 years ago

What is the perimeter of ^PQR with vertices P(-2,9) Q(7,-3) and R(-2,-3) in the coordinate plane?

e-lub [12.9K]

Using the distance formula we can determine the perimeter of PQR.

Distance formula: d=√(x-x1)^2+(y-y1)^2
distance of PR: √(-2+2)^2+(9+3)^2= 12
distance of QR: √(7+2)^2+(-3+3)^2=9
distance of PQ: √(7+2)^2+(-3-9)^2= 15

Perimeter: 12+9+15=36

5 0

3 years ago

Find the tenth term of the geometric sequence, given the first term and common ratio.

Natalija [7]

Answer:

$a_{10}=\dfrac{1}{128}$

Step-by-step explanation:

In the geometric series:

$a_1=4\\ \\r=\dfrac{1}{2}$

The nth term of the geometric sequence can be calculated using formula

$a_n=a_1\cdot r^{n-1}$

In your case, n = 10, then

$a_{10}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^{10-1}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^9\\ \\=2^2\cdot \dfrac{1}{2^9}\\ \\=\dfrac{1}{2^{9-2}}\\ \\=\dfrac{1}{2^7}\\ \\=\dfrac{1}{128}$