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Dominik [7]
3 years ago
5

A car can travel 38 miles on each gallon of gasoline. At that rate, how many gallons of gasoline will it take to travel 190 mile

s?
Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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2 of 6
Kryger [21]

Answer:

£2112

Step-by-step explanation:

To find Gavin's share, sum the parts of the ratio, 4 + 1 = 5 parts

Divide the win by 5 to find the value of one part of the ratio.

£8800 ÷ 5 = £1760 ← value of 1 part of ratio, thus

4 parts = 4 × £1760 = £7040 ← Gavin's share

Now repeat the process with the ratio for his family

1 + 6 + 3 = 10 parts

£7040 ÷ 10 = £704 ← value of 1 part of the ratio, thus

6 × £704 = £4224 ← wife's share

3 × £704 = £2112 ← son's share

Difference = £4224 - £2112 = £2112

Thus his wife gets £2112 more than the son

4 0
3 years ago
I need help with this
maks197457 [2]
Number one : x^6 yz^8
number two : 64x^6 z^12 / y^9
number three : x^9 y^3
number four : y^7/x^7z^3
number five : x^3/5y^2
number six : x^12y^3/z^6
7 0
3 years ago
Cedric has 1 red pen, 1 blue pen, and 1 black pen in his desk. If he randomly takes two of them from his desk without replacemen
lozanna [386]
Maybe it is a 1 out of 3 probability
8 0
3 years ago
7. In some places, a suspension bridge is the only passage over a river. The height of one such bridge, h, in metres, above the
Cloud [144]
Sure. The function is a parabola. Because the coefficient of the x^2 term is positive, it opens upward. that means that it vertex is a minimum point.

You can verify that the vertex is (0,24). That means that at the point x=0, the height of the bridge is 24m. So if the level water rises below 24 m, the bridge is safe to use.
4 0
3 years ago
The perpendicular bisectors of AABC intersect at point<br> G. Find the length of BG.<br> B
Paladinen [302]

Answer:

\overline{GB} = 9

Step-by-step explanation:

The given parameters are;

The point of intersection of the perpendicular bisectors of the sides \overline{BC}, \overline{BA}, and \overline{CA} intersect (meet) at point G

Let D represent the point of intersection of the perpendicular bisector from G to \overline{BC}, we have for ΔBGD and ΔCGD;

\overline{GD} ≅ \overline{GD} by reflexive property

∠GDB = ∠GDC = 90° given that \overline{GD} is the perpendicular bisector of \overline{BC}

Similarly, \overline{DB} ≅ \overline{DC}, also given that  \overline{GD} is the perpendicular bisector of \overline{BC}

Therefore;

ΔBGD ≅ ΔCGD by Side-Angle-Side (SAS) rule of congruency

\overline{GB} ≅ \overline{GC}   by Congruent Parts of Congruent Triangles are Congruent, (CPCTC)

\overline{GB} = \overline{GC} = 9 by definition of congruency

∴ \overline{GB} = 9.

4 0
2 years ago
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