Answer:
The problem is about cases of diabetes in old people through months.
The variable is descrete , because it doesn't admit decimal numbers, it represents people, and people are whole numbers.
The frequency table would be
<h3> Months People</h3>
January 24
February 30
March 20
April 18
May 28
June 12
The total number of people is 132.
The mean would be the total number of people divided by the six months.
![\mu = \frac{132}{6} =22](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7B132%7D%7B6%7D%20%3D22)
Therefore, the mean is 22 people per month.
Remember that the median is the value at the center of the data set, which is between March and April, so
![\frac{20+18}{2}=19](https://tex.z-dn.net/?f=%5Cfrac%7B20%2B18%7D%7B2%7D%3D19)
Therefore, the mean is 19.
The third statistical value is determined by the major frequency. So, the data that repeats the most is February, which means that month encloses the majority of people.
Answer:
x = 1
Step-by-step explanation:
Subtract 3 from both sides
x+ 3 - 3 = 4 - 3
gives x=1
Answer:
After the extended period of time, Pete would have typed 6400 words.
Step-by-step explanation:
Given the data in the question;
In the same time;
number typed word of Pete = 80
type word of Ralph = 50
After a period time;
number of typed word of Pete = ?
number of typed word of Ralph = 4000
so, let x represent the number of typed word by Pete after an extended period.
so
80 words = 50 words
x words = 4000 words
we cross multiply
x × 50 = 4000 × 80
x = ( 4000 × 80 ) / 50
x = 320000 / 80
x = 6400
Therefore, After the extended period of time, Pete would have typed 6400 words.
Answer:
Largest number ins scientific notation: 1.4 x 10⁹ (Diameter of sun)
Step-by-step explanation:
We need to find the largest number ins scientific notation.
The number which has highest degree would be the largest.
In the given options, Diameter of Sun has highest power i.e 10⁹
All other options have lower degrees.
So, largest number ins scientific notation: 1.4 x 10⁹ (Diameter of sun)
Answer:
m = 2
Step-by-step explanation:
Given:
x = 4
y = 6m - 2
a = 8
b = 5
Required:
Value of m
SOLUTION:
x and y are segments of a chord divided when it intersects another chord that also has segments a and b.
According to the Intersecting chords theorem, ![a*b = x*y](https://tex.z-dn.net/?f=%20a%2Ab%20%3D%20x%2Ay%20)
Thus:
![8*5 = 4*(6m - 2)](https://tex.z-dn.net/?f=%208%2A5%20%3D%204%2A%286m%20-%202%29%20)
Solve for m
![40 = 24m - 8](https://tex.z-dn.net/?f=%2040%20%3D%2024m%20-%208%20)
![40 + 8 = 24m - 8 + 8](https://tex.z-dn.net/?f=%2040%20%2B%208%20%3D%2024m%20-%208%20%2B%208%20)
![48 = 24m](https://tex.z-dn.net/?f=%2048%20%3D%2024m%20)
![\frac{48}{24} = \frac{24m}{24}](https://tex.z-dn.net/?f=%20%5Cfrac%7B48%7D%7B24%7D%20%3D%20%5Cfrac%7B24m%7D%7B24%7D%20)
![2 = m](https://tex.z-dn.net/?f=%202%20%3D%20m%20)
The value of m = 2