Answer:
2nd option
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
P (- 8, 1 ) → P' (- 8, - 1 )
Q (- 6, - 8 ) → Q' (- 6, 8 )
R (4, - 3 ) → R' (4, 3 )
Answer:
(-6,6)
Step-by-step explanation:
I'm assuming that there is another root which should be -SQRT(11)
f(x) = x(x-4)(x+SQRT(11))(x-SQRT(11)
Then
f(x) = x^4 -4x^3 - 11x^2 +44x