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Ksenya-84 [330]
3 years ago
13

A jar contains jelly beans, and there are 87 pink, 74 purple, 35 white, 70 black, 25 orange, and 47 green. if two jelly beans ar

e chosen from the jar, what is the probability that both are not the same color
Mathematics
1 answer:
balu736 [363]3 years ago
7 0

\frac{2}{338}
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Use the diagram to answer each part of the question. The image is not drawn to scale.
Mnenie [13.5K]

The height of the tree and the building are 7.6 m and 28.6 m respectively.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Two triangles are similar if they have the same shape and the ratio of their corresponding sides are in the same proportion.

Triangle BGD, CHD and AFD are similar triangles.

CH = 1.6, DH = 8, GH = 30,  GF = 105

FH = GF + GH = 105 + 30 = 135

FD = FH + DH = 135 + 8 = 143; GD = 30 + 8 = 38

Hence, using similar triangles:

BG/CH = GD / DH

BG / 1.6 = 38/8

BG = 7.6 m

Also:

building/CH = DF / DH

building / 1.6 = 143/8

building = 28.6 m

The height of the tree and the building are 7.6 m and 28.6 m respectively.

Find out more on equation at: brainly.com/question/2972832

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5 0
1 year ago
9. Are there any outliers in the data from question #7?
Arisa [49]

Answer:

A) Yes; Week 10 is an outlier since it is the greatest data point.

8 0
2 years ago
Plz need help like now plz
nika2105 [10]
T) -7x+10y=20. M) -3x+y=-2 - ,
2(8x-5y)=35(2) -1(x+y)=-6(-)

-7x+10y=20. -3x+y=-2
16x-10y=70. -x-y=6

9x=90. -4x=4
[x=10] [x= -1]

-7(10)+10y=20. -3(-1)+y=-2
-70+10y=20. 3+y=-2
10y=90. [y= -5]
[y=9]
7 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
Please someone help What is the volume
Kazeer [188]

Answer:

7 because 24-10=4+3=7

Step-by-step explanation:

3 0
3 years ago
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