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ss7ja [257]
3 years ago
12

The parametric equations x = x1 + (x2 − x1)t, y = y1 + (y2 − y1)t where 0 ≤ t ≤ 1 describe the line segment that joins the point

s p1(x1, y1) and p2(x2, y2). use a graphing device to draw the triangle with vertices a(1, 1), b(3, 4), c(1, 7). find the parametrization, including endpoints, and sketch to check. (enter your answers as a comma-separated list of equations. let x and y be in terms of t.)

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.


For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).

... x = 1 + t(3-1)

... y = 1 + t(4-1)

ab = {x=1+2t, y=1+3t}


For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).

... x = 3 + t(1-3)

... y = 4 + t(7-4)

bc = {x=3-2t, y=4+3t}


For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).

... x = 1 + t(1-1)

... y = 7 + t(1-7)

ca = {x=1, y=7-6t}

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Harlamova29_29 [7]

Answer:

(x +10)^2 + (y+6)^2 = 121

Step-by-step explanation:

Given equation :

                        x^2 + y^2 + 20x +12y + 15 = 0

Standard equation of circle :

                                            (x - a)^2 + (y-b)^2 = r^2

We will consider the x terms in the equation first to find a.

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Next consider the y terms to find b.

(y - b)^2 = y^2 -2by + b^2

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b = -6

(x+10)^2 + (y-6)^2 = x^2 +20x +100 + y^2 +12y + 36

                             =x^2 + y^2 + 20x +12y + 136\\

But the given equation constant is 15. So find the difference between 136 and 15 to find the radius : 136 - 15 = 121

Therefore, radius = √121 = 11

<em><u>Equation in standard form : </u></em>

                                         (x +10)^2 + (y+6)^2 = 121

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