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Pepsi [2]
3 years ago
14

A carton of milk contains 1.89 liters. To the nearest whole number, how many 220-milliliter servings are in the container?

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

There are 8 220-mililiter servings in the container, with 130 mililiters left over.

Step-by-step explanation:

The mililiter unit of measure refers to 1/1000 liters. So 220 milliliters is actually 0.22 liters. Therefore, to determine the number of 220 milliliter servings that can fit in 1.89 liters, the following division must be performed:

1.89 / 0.22 = X

8.59 = X

Therefore, 8 servings of 220 milliliters (1,760 ml) could be served, with 130 milliliters left over.

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It is one more than the sum of the first three natural numbers, followed by the 24th letter of the alphabet. Please help
Luda [366]

Answer:

The set of natural numbers is the set of all positive integers, then this set is:

{1, 2, 3, ...}

and the 24th letter of the alphabet is x

Now we want to write the expression given in the sentence "It is one more than the sum of the first three natural numbers, followed by the 24th letter of the alphabet"

We can "break" this in parts, so it is easier to understand.

Then:

"...the sum of the first 3 natural numbers..."

is:

1 + 2 + 3

Then:

"...the sum of the first 3 natural numbers, followed by the 24th letter of the alphabet"

This can be written as:

(1 + 2 + 3) + x

Now we can analyze the complete sentence:

"It is one more than the sum of the first three natural numbers, followed by the 24th letter of the alphabet"

This is equal to the expression we found above plus one, then we can write this as:

[(1 + 2 + 3) + x] + 1

[6 + x] + 1

6 + x + 1

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4 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

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