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GREYUIT [131]
2 years ago
7

What is the length of the strip of seaweed around the outside of the sushi?

Mathematics
1 answer:
SashulF [63]2 years ago
8 0
To find the circumference of a round object, you will take the diameter and multiply is by pi to get 78.5mm

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I need help on this question plz
olganol [36]

The equation of a triangle is A = (1/2)B x H, because it is half of a square. So its a triangle.

8 0
2 years ago
Read 2 more answers
Problem of volume that equals 9 work please
zhuklara [117]

Step-by-step explanation:

l=1

b=3

h=3

l×b×h

9 is the vol

8 0
3 years ago
A ⊆ B means: A is an element of B B is a subset of A B is an element of B A is a subset of B none of the above
Mnenie [13.5K]

Answer:

Step-by-step explanation:

90 is the answer

8 0
3 years ago
Read 2 more answers
Find the trigonometric integral. (Use C for the constant of integration.)
Olin [163]

Suppose we let u=\sin\theta+\cos\theta, so that \mathrm du=(\cos\theta-\sin\theta)\,\mathrm d\theta.

Also, recall the double angle identity for cosine:

\cos(2\theta)=\cos^2\theta-\sin^2\theta=(\cos\theta-\sin\theta)(\cos\theta+\sin\theta)

So, we can rewrite and compute the integral using the substitution, as

\displaystyle\int\cos(2\theta)(\sin\theta+\cos\theta)^3\,\mathrm d\theta

=\displaystyle\int u\cdot u^3\,\mathrm du

=\displaystyle\int u^4\,\mathrm du

=\dfrac{u^5}5+C

=\boxed{\dfrac{(\cos\theta+\sin\theta)^5}5+C}

4 0
3 years ago
A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t
nexus9112 [7]
This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon. 

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s: 

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other: 

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation: 

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation: 

1.1s = 5.1

Last, we divide both sides by 1.1. So s = 4.63. 

This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation: 

2.6s + 7.3
= 2.6 (4.63) + 7.3
= 19.33

1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.
6 0
3 years ago
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