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saveliy_v [14]
3 years ago
13

For which values of x is the inequality 3(1 + x) > x + 17 true?

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:  The correct option is

(D) 8 and 9.

Step-by-step explanation:  We are given to select the correct values of x for which the following inequality is true :

3(1+x)>x+17~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To select the correct values of x, we must solve the given inequality.

From inequality (i), we have

3(1+x)>x+17\\\\\Rightarrow 3+3x>x+17\\\\\Rightarrow 3x-x>17-3\\\\\Rightarrow 2x>14\\\\\Rightarrow x>\dfrac{14}{2}\\\\\Rightarrow x>7.

Since the value of x is strictly greater than 7, so the correct vaues will be 8 and 9.

Option (D) is CORRECT.

Fittoniya [83]3 years ago
3 0
For which values of x is the inequality 3(1 + x) > x + 17 true?
A) 2 & 3
B) 4 & 5
C) 6 & 7
☆☆☆☆☆☆☆☆D) 8 & 9

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I just need 5 please help show work and I’ll give brainliest
Ostrovityanka [42]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

A function f is even if f(-x) = f(x)


f(x)                               f(-x)                                  Are they equal?

----------------------------------------------------------------------------------------

-x^8 + 2x^6-5x           -(-x)^8 + 2(-x)^6 + 5x         No

3 abs(x) - 4                 3 abs(-x) -4                       Yes

log5 x^2                     log5 (-x)^2                        Yes

(6x)^ (1/7)                     (-6x)^(1/7)                          No

e^(x^2-x)                     e^( (-x)^2+x)                      No

(x^8 +5x^2)^(-1)           ( (-x)^8 + 5 (-x)^2) ^(-1)      Yes


Answers with Yes, above are even functions.

Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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