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saveliy_v [14]
2 years ago
13

For which values of x is the inequality 3(1 + x) > x + 17 true?

Mathematics
2 answers:
Andru [333]2 years ago
7 0

Answer:  The correct option is

(D) 8 and 9.

Step-by-step explanation:  We are given to select the correct values of x for which the following inequality is true :

3(1+x)>x+17~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To select the correct values of x, we must solve the given inequality.

From inequality (i), we have

3(1+x)>x+17\\\\\Rightarrow 3+3x>x+17\\\\\Rightarrow 3x-x>17-3\\\\\Rightarrow 2x>14\\\\\Rightarrow x>\dfrac{14}{2}\\\\\Rightarrow x>7.

Since the value of x is strictly greater than 7, so the correct vaues will be 8 and 9.

Option (D) is CORRECT.

Fittoniya [83]2 years ago
3 0
For which values of x is the inequality 3(1 + x) > x + 17 true?
A) 2 & 3
B) 4 & 5
C) 6 & 7
☆☆☆☆☆☆☆☆D) 8 & 9

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Logically Its C

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Because from first and third step we see thied stel lose 1 vertical and one horizontal line.

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Use the formula for the probability of the complement of an event. A coin is flipped 4 times. What is the probability of getting
raketka [301]

Answer: 15/16

Step-by-step explanation:

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P(C) + P(C') = 1

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P(C') = 1 - 1/16

Take the l.c.m

P(C') = (16-1) / 16

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So the probability of getting at least 1 tail is 15/16

7 0
3 years ago
In a triangle ABC, if <B = 60° and the ratio of two sides is a: c= 2: square root 3+1, then <A=
slavikrds [6]

Your answer is 75°.

To answer this question you need to use both the cosine rule and the sine rule. First, we need to find the length of side b by using the cosine rule, where a = 2 and c = √3 + 1. Then you substitute these into the equation:

b² = a² + c² - 2×a×c×cos(B)

b² = (2)² + (√3 + 1)² - 2×2×(√3 + 1)×cos(60)

b² = 4 + 4 + 2√3 - (4 - 4√3)×0.5

b² = 8 - 2 = 6

b = √6

Then you use this length in the sine rule, and find the angle:

\frac{sin(A)}{\sqrt{3}+1 } =\frac{sin(60)}{\sqrt{6} }

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A = 75

I hope this helps! Let me know if you have any questions

7 0
3 years ago
Jim needs to rent a car. A rental company charges $21.00 per day to rent a car and $0.10 for every mile driven.
Ulleksa [173]

Answer:

21d+25\leq 115

Max is 4 days.

Step-by-step explanation:

An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign: ,\leq,\geq.

We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.

We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.

21d + 0.10(250)

We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.

So we write 21d+0.10(250)\leq 115.

To find the number of days he can rent the car, we solve for d using inverse operations.

21d+0.10(250)\leq 115\\21d+25\leq 115\\21d+25-25\leq 115-25\\21d\leq 90\\\frac{21d}{21} \leq \frac{90}{21}\\d\leq 4.3

This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.

3 0
3 years ago
Show 2-(-3) on a number line.
9966 [12]
Just put a closed circle above 5 on the # line.
3 0
2 years ago
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