Don’t listen to the links people -_- they mad annoying
The answer you would be looking for is 2/3 if you reduce them both by 4 you will understand. Sorry if I’m wrong.
<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
3/4 x 2/1 = 6/4
Simplify:
6/4 = 3/2
So, 3/2 or 1.5
A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
Learn more about Vertical Asymptotes:
brainly.com/question/2513623
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