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umka2103 [35]
3 years ago
10

9 tickets numbered 1 to 9 . 3 tickets are drawn one at a time without replacement ,what is probability having alternately odd,ev

en odd
​
Mathematics
1 answer:
gregori [183]3 years ago
5 0

Answer:

there is a 1 in 3 chance for you to get odd even odd.

Step-by-step explanation:

you have a 33 percent chance to get odd even odd

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Iq scores follow a normal distribution with mean 100 and standard deviation 15. give 100 random city college students a standard
kipiarov [429]
About 68% of the people will score between 85 and 115.

The values of 85 and 115 are exactly 15 points away, or 1 standard deviation, away from the mean.

According to the empirical rule, about 68% of the values in a normal distribution are within 1 standard deviation of the mean.
4 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Find the measurement parallelogram.<br> I need help please, thank you.<br> I need explanation
blondinia [14]

Answer:

2.) 145°

4.) 50°

Step-by-step explanation:

2.) First find the measure of Angle Y, since they are supplementary;

∠Z + ∠Y = 180

35 + ∠Y = 180

∠Y = 180 - 35

∠Y = 145°

So ∠X would be 145° as well

4.) First find the measure of Angle F, since they are supplementary;

∠C + ∠F = 180

130 + ∠F  = 180

∠F = 180 -130

∠F = 50°

So ∠E would be 50°

(I didn't explain it much in detail, since this question is similar to the previous that i answered :)

Hope this helps!

4 0
3 years ago
Write down in terms of n,
mojhsa [17]
A) is counting down by 3
B) is counting up by 5
4 0
3 years ago
PUPUL 2
grandymaker [24]

Answer:

37.045

Step-by-step explanation:

4 0
3 years ago
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