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Vsevolod [243]
3 years ago
14

What value of n solves the equation 2^n =1/8

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
2^n=\cfrac{1}{8}\qquad \boxed{8=2^3}\qquad 2^n=\cfrac{1}{2^3}\implies 2^n=2^{-3}
\\\\\\
\textit{the base is the same, the exponents must also be the same}\quad  n=-3
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