Answer: 13.5π≈42.41
Step-by-step explanation:
Basically it is asking for the circumference of this cylinder.
#1 Find the circumference of the circle base
Formula to use: 2πr
2πr=2π(1.5)=3π
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#2 Find the area of the circle base
Formula to use: πr²
πr²=π(1.5)²=2.25π
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#3 Find the area of body of the cylinder
Formula to use: lw
300cm=3m
l (length)= 3π (since the body of the cylinder the basing on the circumference of the circle base)
w (width)= 3
lw=3π×3m=9π
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#4 Add all of them together
There are 2 base and one body
2.25π×2+9π=13.5π
V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
[ Answer ]
[ Explanation ]
- Change
To Percent
-------------------------------------
Is The Same As 5 ÷ 2
5 ÷ 2 = 2.5
- Convert Decimal To Percentage
2.5 · 100 = 250
250%
![\boxed{[ \ Eclipsed \ ]}](https://tex.z-dn.net/?f=%5Cboxed%7B%5B%20%5C%20Eclipsed%20%5C%20%5D%7D)
-4m-8=-8-4m
+4 +4
__________
-8=-8
or
1=1
Answer:
It's A
Step-by-step explanation:
It's just moving the equation to the right 4 units. There's no stretch, compression, or reflection.
