3 years ago

Translation: 4 units left and 4 units up J(−1, −2), A(−1, 0), N(3, −3)

Mathematics

1 answer:

deff fn [24]3 years ago

3 0

Answer:

J(-5,2), A(-5,4), and N(-1,1)

Step-by-step explanation:

You might be interested in

F(x)=x^3−9x

klio [65]

i don’t know but you could prob use photo math. that would hell

3 0

3 years ago

Read 2 more answers

Find the ratio in which the line joining the points (2, 4, 16) and (3, 5, -4) is divided by the plane 2x – 3y+ z+ 6 = 0. Also fi

Nastasia [14]

Answer:

Step-by-step explanation:

let the plane intersects the join of points in the ratio k:1

let (x,y,z) be the point of intersection.

$x=\frac{3k+2}{k+1} \\y=\frac{5k+4}{k+1} \\z=\frac{-4k+16}{k+1} \\\because ~(x,y,z)~lies~on~the~plane.\\2(\frac{3k+2}{k+1} )-3(\frac{5k+4}{k+1} )+\frac{-4k+16}{k+1} +6=0\\multiply~by~k+1\\2(3k+2)-3(5k+4)+(-4k+16)+6(k+1)=0\\6k+4-15k-12-4k+16+6k+6=0\\-7k+14=0\\k=2\\x=\frac{3*2+2}{2+1} =\frac{8}{3} \\y=\frac{5*2+4}{2+1}= \frac{14}{3} \\z=\frac{-4*2+16}{2+1} =\frac{8}{3}$