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3 years ago

Which statement is true about the marginal frequencies

Mathematics

2 answers:

Tcecarenko [31]3 years ago

3 0

Answer:

Step-by-step explanation:

If U add up all the people who played sports and all the 10th graders u will get 191 and 97 and it just said I got it right

son4ous [18]3 years ago

3 0

Answer:

Step-by-step explanation:

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Does -2(z+3)-z=-z-4(z+2) have one,zero or infinite solutions

Andrew [12]

Hello from MrBillDoesMath!

Answer:

One solution (z = -1)

Discussion:

-2(z+3)-z=-z-4(z+2) =>

-2z -6 -z = -z -4z - 8 =>

-3z -6 = -5z -8 => add 6 to both sides

-2z = -5z -2 => add 5z to both sides

3z = -5z +5z -3 =>

3z = -3 =>

z = -1

Thank you,

MrB

6 0

4 years ago

Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla

krek1111 [17]

B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.

8 0

3 years ago

Read 2 more answers

Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu

Alona [7]

Answer:

We have the equation

$c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]$

Then, the augmented matrix of the system is

$\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]$

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

$\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]$

This matrix is in echelon form. Then, now we apply backward substitution:

$8c_4=0\\c_4=0$

$4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0$

$3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0$

$c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0$

Then the system has unique solution that is $(c_1,c_2c_3,c_4)=(0,0,0,0)$ and this imply that the vectors $v_1,v_2,v_3,v_4$ are linear independent.

4 0

3 years ago

a person is standing on top of a smaller building looking across the street at a taller building, which is 260 feet away horizon

Anuta_ua [19.1K]

The height of the smaller building is 94.63 feet, computed using the trigonometric ratios.

In the question, we take AB to be the taller building, where A is its top and B is its base, CD to be the shorter building, where C is its top and D is its base, and CE to be the perpendicular from C to AB.

Given that the horizontal distance between the two buildings is 260 feet, we can say that BC = CE = 260 feet.

The angle of elevation from the top of the shorter building to the top of the taller building is 30°, that is, ∠ECA = 30°.

The angle of depression from the top of the shorter building to the base of the taller building is 20°, that is, ∠ECB = 20°.

When ∠ECB = 20°, then ∠CBD = 20°, as they are alternate angles.

We are asked to find the height of the shorter building, that is, we are asked to find CD.

In ΔCBD,

tan ∠CBD = CD/BD {perpendicular/base},

or, tan 20° = CD/260,

or, CD = 260*tan 20° = 260*0.36397023426 {∵ tan 20° = 0.36397023426},

or, CD = 94.6322609092.

Therefore, the height of the smaller building is 94.63 feet, computed using the trigonometric ratios.

Learn more about heights and distances at

brainly.com/question/2004882

#SPJ4

7 0

2 years ago

HELP ASAP HELP ASAP HELP ASAP HELP ASAP

Shtirlitz [24]

The equation is P= 2w + 2(w+4.1)

The width is 8.2cm

5 0

3 years ago