Question

What is the polar form of the complex number 4−6i? Keep z in its simplest radical form and round θ to the nearest degree.

Answer 1

Answer:

D

Step-by-step explanation:

$z=r(cos \theta+\iota sin \theta)=4-6 \iota\\r cos \theta=4\\r sin \theta=-6\\square~and~add\\r^2(cos^2 \theta+sin ^2\theta)=4^2+(-6)2=16+36\\r=\sqrt{52} =2\sqrt{13} \\cos \theta >0~and~sin ~\theta$