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pav-90 [236]
3 years ago
14

2) (a^3-2a)-(3a^2-4a^3

Mathematics
1 answer:
mylen [45]3 years ago
5 0

Answer:

a x (a2-2)

Step-by-step explanation:

the 2 is supposed to be above the a I don't know how to that while typing.

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Which function has a range of y&lt;3?<br> y=3(2)<br> y=2(3)<br> O y=-(2)* +3<br> O y= (2)* - 3
VARVARA [1.3K]

option C is correct.

<u>Step-by-step explanation:</u>

If a function is defined as

f(x)=a^x where, a>0, then the range of the function is greater than 0.

a^x>0               .... (1)

Option A: Using inequity (1),

2^x>0

Multiply both side by 3.

3(2^x)>0

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

3^x>0

Multiply both side by 2.

2(3^x)>0

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

2^x>0

Multiply both side by -1.

-2^x

Add 3 on both the sides.

-2^x+3

y

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

2^x>0

Subtract 3 from both the sides.

2^x-3>-3

y>-3

The range of second function is y>-3. Therefore option D is incorrect.

7 0
3 years ago
What is the slope of this line??
USPshnik [31]
Picture isn't showing up there
4 0
3 years ago
Read 2 more answers
Given: AB = 12
Alexxx [7]

In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

=6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore,  AC = CB and thus In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

Learn more about midpoint from

brainly.com/question/6364992

#SPJ1

3 0
1 year ago
Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the a
sveticcg [70]

Complete question is;

An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be represented using the sequence shown.

110, 130, 150, 170, ...

Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the amount of money currently earned?

Answer:

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

Step-by-step explanation:

Electrician earns $110 dollars after working for 1 hour.

We were told his total pay based on number of hours worked can be represented by: 110, 130, 150, 170...

This means that writing it down as a function, we can say;

f(1) = $110, f(2) = $130 e.t.c

Now,since we want to express a recursive formula to explain the question, then let's say after the 1 hour worked, he earned $110, then the hour after that, his total is $130,then the hour after that, his total is $150.

This means that he earns an additional $20 each hour.

Thus;

f(x + 1) = f(x) + 20

Where x is number of hours and f(x) is payment after x number of hours

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

5 0
3 years ago
What is the estimate for square root of 22
tigry1 [53]
<span>16=4²
25=5² 
</span>So that means the square root of 22 is between 4 and 5.
Square 4.5 
4.5² = 20.25 
<span>4.5 < √22 < 5
So the nearest whole number would be 5.
</span>
Happy Holidays~
5 0
3 years ago
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