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3 years ago

What is 772,000 written in scientific notation?

Mathematics

1 answer:

SashulF [63]3 years ago

3 0

When using scientific notation, the number (that is not 10 to the nth power) is always between 1 and 10.

For 772,000.0, I've added the decimal to the correct place. In order to get a number between 1 and 10, we will need to move the decimal 5 places. This leaves us with 7.72 x 10^5.

But, as I see that the answer above is not an option, and the only correct answer would be A, It is the only one between 1 and 10, I feel that there may be a mistake. For A to be correct, the original number would be 7,720,000,000.

Best answer: A

Hope this helps!! :)

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How do you do this question?

e-lub [12.9K]

Answer:

D. dA/dt = 4h dh/dt in²/sec

Step-by-step explanation:

Given:

A = wh

w = 2h

Substitute:

A = 2h²

Take derivative with respect to time:

dA/dt = 4h dh/dt

dA/dt has units of in²/sec.

7 0

3 years ago

If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

lions [1.4K]

Answer:

-1280

Step-by-step explanation:

There are 2 ways you could do this. You could just do the question until you come to the end of f(4). That is likely the simplest way to do it.

f(1) = 160

f(2) = - 2 * f(1)

f(2) = -2*160

f(2) = -320

f(3) = -2 * f(2)

f(3) = -2 * - 320

f(3) = 640

f(4) = - 2 * f(3)

f(4) = - 2 * 640

f(4) = - 1280

I don't know that you could do this explicitly with any real confidence.

5 0

3 years ago

Read 2 more answers

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$