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ivolga24 [154]
3 years ago
9

In a class of pupils, 11 play the flute and piano.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

The answer is 29

Step-by-step explanation:

11+10+5+3=29

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Wittaler [7]
I believe the answer is height
3 0
4 years ago
What is the correct symbol?
Nadusha1986 [10]

Answer:

Since 10/9 is greater than 1, multiplying by 10/9 makes the value larger

Step-by-step explanation:

Step 1: Solve the fraction

10/9 = 1.1112

Therefore 10/9 > 1

Step 2: Multiple the fraction by itself

10/9 x 10/9 = 100/81

Convert fraction to decimals

100/81 = 1.2345678901.....

1.234567901 > 1.1112

Therefore 10/9 x 10/9 is bigger than 10/9

3 0
4 years ago
a chord of 12cm long of 8cm is away from the of the circle what is the lenght of the chord which is 6cm away from the centre
lana66690 [7]

Answer:

The length of the chord is 16 cm

Step-by-step explanation:

Mathematically, a line from the center of the circle to a chord divides the chord into 2 equal portions

From the first part of the question, we can get the radius of the circle

The radius form the hypotenuse, the two-portions of the chord (12/2 = 6 cm) and the distance from the center to the chord forms the other side of the triangle

Thus, by Pythagoras’ theorem; the square of the hypotenuse equals the sum of the squares of the two other sides

Thus,

r^2 = 8^2 + 6^2

r^2= 64 + 36

r^2 = 100

r = 10 cm

Now, we want to get a chord length which is 6 cm away from the circle center

let the half-portion that forms the right triangle be c

Using Pythagoras’ theorem;

10^2 = 6^2 + c^2

c^2 = 100-36

c^2 = 64

c = 8

The full

length of the chord is 2 * 8 = 16 cm

5 0
3 years ago
Liang enlarged a photograph to 1 3/4 times it original size. The original photograph was 5 inches wide. What was the width of th
Alja [10]
8.75 inches
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7 0
4 years ago
The length of a rectangle is 4 cm less than it’s width. If the area of the rectangle is 165 cm^2. What are the dimensions of the
Monica [59]

Answer:

The dimensions are 11 cm by 15 cm

Step-by-step explanation:

Area of a rectangle = (length)(width).

Let L represent the length and W the width.

Since L = W - 4, we have

Area of rectangle = (W - 4)W = 165 cm^2.

Thus, w^2 - 4W - 165 = 0.  We can solve for W using the quadratic formula:

a = 1, b = -4 and c = -165.  Thus,

        -(-4) ± √ [ (-4)² - 4(1)(-165) ]

W = ---------------------------------------

                        2

         4 ± √ [16 + 660 ]

W = ------------------------------

                       2

         4 ± √ [ 676 ]                    4 ± 26

W = -----------------------  =   W = -------------  =  W  = 2 ± 13

                  2                                  2

Thus, W is 2 + 13 = 15.  It cannot be negative, so we discard 2 - 13 = -11.

If the width, W, is 15, then the length is 4 less, or L = 11.

The dimensions are 11 cm by 15 cm

6 0
4 years ago
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