All categories

3 years ago

Question 1- Write an Integer for the Situation below:

1 answer:

6 0

13 ft below sea level.....0 is sea level....so 13 feet below 0 is -13 <==

20 problems.....100/20 = 5 points per problem....so if the student got an 80%, then they missed 4 problems and correctly answered 16 <==

opposite of - |-7|.....- |-7| = - 7.....the opposite would be 7 <==

You might be interested in

Solve by elimination: -5/7-11/7 x=-y, 2y=7+5x

Veronika [31]

Answer:

x= -3

y= -4

Step-by-step explanation:

If 11/17 and x goes together then this is what I got. Oh plug them in in case its wrong. Good Luck

7 0

2 years ago

Two straight lines VZ and YW intersect at X

Alexeev081 [22]

Answer:

∠WVX = 35°

Step-by-step explanation:

Look at the rough draw.

As you can see,

VW ║ YZ

So ∠XWV is congruent to ∠XYZ through alternate interior angle.

We can solve ∠WVX by considering the two other angles, 88° and 57°.

Total angle of a triangle is 180°.

So,

? + 88 + 57 = 180

? + 145 = 180

? = 180 - 145

? = 35°

5 0

3 years ago

What’s the linear equation for (1,21)(2,33)(3,45)(4,57)

nalin [4]

The linear equation representing the above said pair of points is "y=12x+9"

Step-by-step explanation:

The given set of points are

x Y

1 21

2 33

3 45

4 57

For finding the linear equation for the given sets of value

We must know the generic form of a linear equation is y=m*x + c

m= slope of the line where y= Δy/Δx

Δy= change in y value

Δx= change in x value

Thus slope ”m” = 33-21/2-1 = 12

we put slope “m” in the equation which becomes y=12x+c

Now we put any of the set value in the equation

33= 12*2+c ∴ c=9

Hence required linear equation is y=12x+9

7 0

3 years ago

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

I NEED HELP ON QUESTION B AND C ASAP.

ipn [44]

Answer:

See below

Step-by-step explanation:

Assumed the dimensions of the top and bottom parts are identical.

Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:

h = 1.8 cm - 0.3 cm = 1.5 cm

Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.

V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³

<u>Total sand in the bottom part:</u>

7.96 + 4.6 = 12.56 cm³

<u>Time taken:</u>

12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds

8 0

2 years ago