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3 years ago

The middle 83.12% of all Z values are between

Mathematics

1 answer:

Lerok [7]3 years ago

3 0

Answer:so where is the question

Step-by-step explanation:plzz ask probably

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Help ASAP please! Please explain it, thanks in advance!

Oliga [24]

Ally ran 5 miles in 36 minutes.
Ally's speed is (5 miles)/(36 minutes) = 0.13888 miles per minute.
At that speed, Ally would run 6 miles in (6 miles)/(0.13888 miles/min) = 43.2 minutes.
Ally runs faster than Sami, so Sami must take longer to run 6 miles than Ally.
The only time that is longer than 43.2 minutes is 48 minutes.

7 0

3 years ago

Is the square root of any positive number irrational

ser-zykov [4K]

No because if it is the square root of 100, then it is rational, hope this helps

5 0

3 years ago

Help me with this math question

nasty-shy [4]

Answer:

$\huge \boxed{K=20}\checkmark$

B. 20

Step-by-step explanation:

First, you divide by 5 from both sides of equation.

$\displaystyle \frac{5k}{5}=\frac{100}{5}$

Simplify, to find the answer.

$\displaystyle 100\div5=20$

$\huge \boxed{K=20}$ , which is our answer.

6 0

3 years ago

Read 2 more answers

Consider the set {4, 5, 7, 7, 8, 8, 12, 13, 13, 15, 18, 20, 22, 24, 26, 27, 27, 37, 43}. What would be an appropriate interval t

adelina 88 [10]

Proper interval would be 5

8 0

3 years ago

There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there

vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3>Solution:</h3>

Given, There are "x" number of students at helms.

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

$\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}$

Thus there will be 1.078x students in next year

3 0

3 years ago