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prohojiy [21]
3 years ago
8

16.2 Jumping Rope

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

Percentage of Diego's time is 75%.

Step-by-step explanation:

Given : Jumping Rope  hool held a jump-roping contest. Diego jumped rope for 20 minutes.  A school held a jur  Jada jumped rope  for 15 minutes.

To find : What percentage of Diego's time is that?​

Solution :

Diego jumped rope for 20 minutes.

Jada jumped rope for 15 minutes.

Percentage of Diego's time is given by,

\text{Percentage change}=\frac{\text{Jada time}}{\text{Diego time}}\times 100

\text{Percentage change}=\frac{15}{20}\times 100

\text{Percentage change}=75\%

Therefore, percentage of Diego's time is 75%.

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Answer: f(x) = -0.016x² + 1.6x

Step-by-step explanation:

If the lenght of the road over the arch is 100m, we can consider a coordinate plane and say that the road starts at point (0,0) and finishes at (100,0). The vertice of the parabola is at point (50,40), because the maximum height is 40 and it is always in the middle point of the roots.

So, we have

(0,0) (50,40) (100,0)

A quadratic function is always on the form: f(x) = ax² + bx + c

0 = a0² + b0 + c

40 = a50² + b50 + c

0 = a100² + b100 + c

0 = a0² + b0 + c → c = 0 ∴

40 = a50² + b50

0 = a100² + b100

_________________________

2500a + 50b = 40 (*2)

10000a + 100b = 0

_________________________

5000a + 100b = 80

10000a + 100b = 0 (-)

__________________________

-5000a = 80

-a=80/5000

a=-0.016

∴

2500a + 50b = 40

2500.(-0.016) + 50b = 40

-40 + 50b = 40

50b = 80

b = 80/50

b = 1.6

This way f(x) = -0.016x² + 1.6x

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