All categories

3 years ago

Find the solution set.

Mathematics

1 answer:

kow [346]3 years ago

7 0

Answer: 5, -5

Step-by-step explanation:

There are only 2 square roots of 25: plus and minus 5.

You might be interested in

Sarah received 55 for her birthday. She used some of that money to buy 333 shirts priced at m dollars each.

Fudgin [204]

Answer:

You need to tell me (everyone) what M is or we can't figure out what the answer is.

Step-by-step explanation:

5 0

3 years ago

makayla has $8 to buy at a school fair each ticket cost $1.50 which inequality best represents how many tickets she can buy

ivolga24 [154]

Answer:

Step-by-step explanation:

If she only has $8, she can't spend more than that. In other words, she can spend ≤$8.

If each ticket is $1.50 per ticket, the inequality that represents how many tickets she can buy if x represents the number of tickets, is

1.5x ≤ 8

6 0

3 years ago

What are three rational numbers between 0.2 and 0.3 (one must be a fraction)?

sveta [45]

It would be 2/5 but the numbers between is 2/10 and 3/10

4 0

3 years ago

Read 2 more answers

What is the slope-intercept form of 8x - y - 6 = 0?

Liula [17]

The slope intercept form is Y=mx + b
8x - y - 6=0
-8x -8x
-y= -6+8x = 0
+6 +6
-y = 8x + 6

I hope you understand.

4 0

3 years ago

Read 2 more answers

You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2

defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

$P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715$

Probability a unit is defective and from manufacturer A:

2% of 43%. So

$P(A \cap B) = 0.02*0.43 = 0.0086$

What is the probability that it came from manufacturer A?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015$

0.5015 = 50.15% probability that it came from manufacturer A.

4 0

3 years ago