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olga_2 [115]
3 years ago
9

I need help simplifying a math problem. It is (x^2 * x^-3)^4

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0
(x^2 \times x^{-3})^4 \\ \\ (x^{2-3})^4 \ / \ product \ rule \\ \\ (x^{-1})^4 \ / \ simplify \\ \\ x^{-4} \ / \ simplify \\ \\ \frac{1}{x^4} \ / \ negative \ power \ rule \\ \\ Answer: \frac{1}{x^4}
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How do you do this question?
r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

s = 1/216 u^(³/₂)

Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

s = (145√145 − 1) / 216

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Step-by-step explanation:

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To determine the perimeter of the triangle given the vertices, calculate the distances between pair of points. For the first pair (-5,1) and (1,1), the distance is 6. For the next pair, (1,1) and (1, -7), the distance is 8. Lastly, for the pair of points (-5,1) and (1, -7), the distance is 10. Adding all the distance will give the perimeter of the triangle. Thus, the perimeter is 24. 
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