The equation in slope-intercept form represents a line that is parallel to y = 12x − 2 and passes through the point (−8,1) is y = 12x + 97
<em><u>Solution:</u></em>
Given that we have to write the equation in slope intercept form for line that is parallel to y = 12x − 2 and passes through the point (−8, 1)
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ---- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given equation of line is y = 12x - 2
On comparing the above equation with eqn 1,
m = 12
Thus slope of line is 12
We know that slopes of parallel lines are equal
Therefore, slope of line parallel to given line is also 12
Given point is (-8, 1)
We have to find the equation of line passing through (-8, 1) with slope m = 12
Substitute m = 12 and (x, y) = (-8, 1) in eqn 1
1 = 12(-8) + c
1 = -96 + c
c = 97
Substitute c = 97 and m = 12 in eqn 1
y = 12x + 97
Thus the required equation of line is found
