Answer:
addition first
Step-by-step explanation:
PMDAS 1
P:Parenthesis 2
M:Multiply 3
D:Divide 4
A:Add 5
S:Subtract 6
Adding is before subraction
Answer:192
Step-by-step explanation:
Isolate y in the first equation.
![2y = 10x](https://tex.z-dn.net/?f=2y%20%3D%2010x)
![y = 5x](https://tex.z-dn.net/?f=y%20%3D%205x)
--------------------------
Then plug this into the second equation
![\frac{x^2}{64}-\frac{y^2}{36} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B64%7D-%5Cfrac%7By%5E2%7D%7B36%7D%20%3D%201)
![\frac{x^2}{64}-\frac{(y)^2}{36} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B64%7D-%5Cfrac%7B%28y%29%5E2%7D%7B36%7D%20%3D%201)
![\frac{x^2}{64}-\frac{(5x)^2}{36} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B64%7D-%5Cfrac%7B%285x%29%5E2%7D%7B36%7D%20%3D%201)
![\frac{x^2}{64}-\frac{25x^2}{36} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B64%7D-%5Cfrac%7B25x%5E2%7D%7B36%7D%20%3D%201)
--------------------------
So
the final answer is choice A
Essentially this is asking you to sum the first three values of the geometric series that starts with i being 1 and has the rule of (
).
Since we must sum the first <em>three </em>geometric values we need to see what the value of i will be for the first three. The sigma notation shows us that the first i will be equal to 1. This means the second i is 2 and the third i is 3.
Knowing this you can plug in the corresponding i values into (
) and sum it all together
(
) + (
) + (
)
(
) + (
) + (
)
(
) + (
) + (
)
(8) + (2) + (
)
10 + ![\frac{1}{2})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%29)
10.5
Hope this helped!
~Just a girl in love with Shawn Mendes