Question

Please I need help!!!

Answer 1

Isolate y in the first equation.

$2y = 10x$

$y = 5x$

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Then plug this into the second equation

$\frac{x^2}{64}-\frac{y^2}{36} = 1$

$\frac{x^2}{64}-\frac{(y)^2}{36} = 1$

$\frac{x^2}{64}-\frac{(5x)^2}{36} = 1$

$\frac{x^2}{64}-\frac{25x^2}{36} = 1$

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So the final answer is choice A