Answer Ox<1-
Step-by-step explanation:
well, since each bar is parallel to the adjacent one, so if A || B || C || D || E || F, then A || F.
now, for the angles, Check the picture below.
Answer:
B. $2862
Step-by-step explanation:
Using n=5 in the given equation, we get ...
A(5) = 2700 + (5-1)(.015·2700) = 2700 +4(40.50)
A(5) = 2862.00
In year 5, you will have $2862 in the account.
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<em>Comment on the given equation</em>
The given equation tells you the amount in the account at the <em>beginning</em> of the year, before it earns any interest. Since that is the equation given, we presume that is the answer desired. In most "account balance" problems, you are interested in the amount at the <em>end</em> of the interest-earning period.
Answer:
no its false because p v q can only be true if both are true
Step-by-step explanation:
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
