Outside
length is 7 inches
Outside Width
is 5 inches.
SOLUTION
Length of outside edge = 7 inches
Scale Factor: 1in = 2.5ft
New length of outside edge = (7 * 2.5)ft
New length = 17.5ft
Width of outside edge = 5 inches
Scale Factor: 1in = 2.5ft
New width of outside edge = (5 * 2.5)ft
New Width = 12.5ft
Therefore, the new dimension of the outside edges of the
frame is 17.5ft by 12.5ft
Step 1 : Setting up the problem
Write the coefficients of the dividend in the same order. For missing terms, enter the co-efficient as zero. Set the divisor equal to zero and use that number in the division box.
The problem now looks as follows:
-1 | 12 5 3 0 -5
Step 2 : Bring down the first co-efficient and write it in the bottom row.
-1 | 12 5 3 0 -5
______________________ 12
Step 3 : Multiply the first coefficient with the divisor and enter the value below
the next co-efficient. Add the two and write the value in the bottom row.
-1 | 12 5 3 0 -5
_____-12_______________ 12 -7
Step 4 : Repeat Step 3 for rest of the coefficients as well:
-1 | 12 5 3 0 -5
____________7 ___________ 12 -7 10
-1 | 12 5 3 0 -5 ______________ -10______ 12 -7 10 -10
-1 | 12 5 3 0 -5 ____________________ 10_ 12 -7 10 -10 5
The last row now represents the quotient coefficients and the remainder. Co-efficients of Quotient are written one power less than their original power and the remainder is written as a fraction.
Answer :12x^3-7x^2+10x-10+5/(x+1) where the last term denotes the remainder and the rest is the quotient.
Answer:
6 x n = 6n
Step-by-step explanation:
2 hours = 60*2 = 120 minutes
120/120 = 1
Margie handed out 1 flyer every minute
Jaxon handed 18/15 = 1.2 flyers per minute
so Jaxon is faster
Answer:
Step-by-step explanation:
Given that you and a friend play a game where you each toss a balanced coin.
If the upper faces on the coins are both tails, you win $1;
if the faces are both heads, you win $2;
if the coins do not match (one shows a head, the other a tail), you lose $1 (win (−$1)).
Let Y be the amount won
Then Y can take values as 1,2 and -1

The above is the probability distribution for Y.