This is essentially asking how many different ways to partition 6 into 3 segments.
I am assuming "no ball in a box" is not allowed.
6 can be partitioned as
(4,1,1), (3,2,1), and (2,2,2)
So, calculate each partition, we get
(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)
= 15 + 20*3 + 15*6
=165
Let x be the certain number and that six time this number may be expressed as 6x. Based on the conditions presented above, the sum of 6x and 8 should be equal to 32. This may be mathematically expressed as,
6x + 8 = 32
Therefore, the answer is fourth choice.
Answer:
add 5 then multiply by 1/2
Step-by-step explanation:
Twice a number is 2n.
The difference of twice a number and five 2n - 5.
The difference of twice a number and five is three. 2n - 5 = 3
2n - 5 = 3
2n - 5 + 5 = 3 + 5 (1) add 5
2n = 8
1/2*2n = 1/2*8 (2) multiply by 1/2
n = 4
Answer:
4
Step-by-step explanation:
It’s either b or d. Hope this helps! :)
