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Korolek [52]
3 years ago
15

Solve the system .....................​

Mathematics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

The correct answer is first option

(2, 3)

Step-by-step explanation:

It is given that,

3y = -x + 11  and

x + 4y = 14

<u>To find the solutions</u>

The given equation can be written as,

x + 3y = 11 --------(1)

x + 4y = 14  -------(2)

Subtract (1)  from (2) we get

y = 3

Substitute vale of y in eq(1)

x + 3*3 = 11

x = 11 - 9 = 2

Therefore x = 2 and y = 3

The correct answer is first option

Leya [2.2K]3 years ago
7 0

Answer:

first option

(2, 3)

Step-by-step explanation:

We have the following system of linear equations

\left \{{{3y=-x+11} \atop {x+4y=14}} \right.

This is the same as

\left \{{{x + 3y=11} \atop {x+4y=14}} \right.

To solve the system multiply the first equation by -1 and then add it to the second equation.

-1*(x+3y)=11*(-1)

-x -3y=-11\\x+4y=14

-----------------

y = 14-11

y = 3

substitute y = 3 in any of the two equations and then solve for x

x+4(3)=14\\x+12=14\\x =14-12\\x = 2\\

x =2

The answer is the first option

(2, 3)

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