They didn’t use the distributive property correct because they didn’t multiply 5x3
Answer:
36.58% probability that one of the devices fail
Step-by-step explanation:
For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
A total of 15 devices will be used.
This means that 
Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.
This means that 
What is the probability that one of the devices fail?
This is 


36.58% probability that one of the devices fail
Answer:
A C(x) =2x³+2x²-18x-11
Step-by-step explanation:
C(x) = W(x) - D(x)
plug W(x) and D(x) into equation
C(x) = 3x³+4x²-18x+4 - (x³+2x²+15)
add like terms now
C(x) =2x³+2x²-18x-11
Answer:
83438143e + 21
Step-by-step explanation:
83438143e + 21
Answer: 2:1
Step-by-step explanation:
The original ratio would be 12:6 but can be simplified to 2:1
hope it helps :)