Answer:
<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>
Step-by-step explanation:
6y - 5z = -8 .......... Equation 1
3z = -6 ................... Equation 2
4x - 3y - 2z= 21...... Equation 3
<u>First solve for z in Equation 2</u>
That's
3z = - 6
Divide both sides by 3
<h3>z = - 2</h3>
Next substitute the value of z into Equation 1 in order to find y
We have
6y - 5(-2) = - 8
6y + 10 = - 8
6y = - 8 - 10
6y = - 18
Divide both sides by 6
<h3>y = - 3</h3>
Finally substitute the values of y and z into Equation 3 to find the value of x
That's
4x - 3(-3) - 2(-2) = 21
4x + 9 + 4 = 21
4x + 13 = 21
4x = 21 - 13
4x = 8
Divide both sides by 4
<h3>x = 2</h3>
So the solutions are
<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>
Hope this helps you
In this equation w = -1.1
In order to find this, get all w values to the right side and all numbers to the left side.
-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms
-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides
-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides
13.8w = -15.18 -----> divide both sides by 13.8
w = -1.1
Answer:
Step-by-step explanation:
ABC have sides: 5, 7 and 10
5^2 + 7^2 = 25+47 = 72 < 10^2
so triangle ABC is obtuse
JKL has sides: 12, 35 and 37
12^2 + 35^2 = 144 + 1225 = 1369 = 37^2
so triangle JKL is right-angled
PQR has sides 12, 10 and 16
12^2 + 10^2 = 144 + 100 = 244 > 16^2
so triangle PQR is acute
