Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)
1 answer:
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Actually Welcome to the Concept of the Inverse of real function.
Let's consider here, g(n) = y ,
so we get as,
no, cubing the power both side we get as,
=>
now,
so finally, we get as,
=>
hence,here, n = inverse of the g(n) function.
so,
g^-1 (n) = 2y^3+1.
Answer:
x ≥ -7
Step-by-step explanation:
Divide both sides by 6
Then to graph it, you can make a number line
down 3 unit mean -3 outside root
right 2 unit mean -2 inside root,
so the answer is