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Tresset [83]
4 years ago
12

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

Mathematics
1 answer:
BabaBlast [244]4 years ago
5 0

Answer:

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

Step-by-step explanation:

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

The solution is attached.

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next distribute the negative 5, you will get - 40m, then 30.

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3 years ago
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Answer:

18.0277563773 yards

Step-by-step explanation:

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So, using what I’m being given:

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Answer:

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