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Grace [21]
3 years ago
12

Simplify the difference. (4w2 – 4w – 8) – (2w2 + 3w – 6)

Mathematics
1 answer:
Pavel [41]3 years ago
8 0
Answer is 2w^2 - 7w - 2
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This is due next period. I need answers and a small explanation/work.
vlada-n [284]

1) Cancel out the common factor which in this case is 8 \frac{16m^2}{24m^7} = \frac{2m^2}{3m^7}

2)First apply exponent rule \frac{n(n+7)}{4n(n+7)}\\ now cancel out the common factors which are n and n+7 leaving you with \frac{1}{4}=0.25

3)Factorize \frac{(x+2)(x-12)}{x+2}cancel out the common factor in this case x+2 leaving you with x-12

4) Factorize \frac{(-3w+1)(3w-1)}{4(3w-1)} cancel out the common factor in this case 3w-1 leaving you with \frac{-3w+1}{4}

5) In the picture

6)In the picture

I am REALLY tired sorry I wont be able to do the rest, I hope these are helpful :)

6 0
2 years ago
Please round to the nearest tenth if possible.
Butoxors [25]
\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
\cfrac{6000~\underline{lbs}}{\underline{day}}\cdot \cfrac{ton}{2000~\underline{lbs}}\cdot \cfrac{7~\underline{day}}{week}\implies \cfrac{6000\cdot 7~ton}{2000~week}\implies 21.00\frac{ton}{week}

\bf -------------------------------\\\\
\cfrac{2~\underline{lbs}}{\underline{week}}\cdot \cfrac{16~oz}{\underline{lbs}}\cdot \cfrac{\underline{week}}{7~day}\implies \cfrac{2\cdot 16~oz}{7~day}\implies \cfrac{32~oz}{7~day}\approx 4.57\frac{oz}{day}
8 0
3 years ago
Which is factorial using integers?<br> a) y+25<br> b) y^2-25<br> c) y^2+25<br> d) y-10<br> e) y^2+10
Masteriza [31]

Answer:

i feel like its A or D i could be wrong but i believe its one of the two

6 0
2 years ago
Which pair of terms can be used to represent any two consecutive odd numbers?
lbvjy [14]
Odd integers are 2 apart from each other (in between them is an even number)

x and x+2 is answer
7 0
3 years ago
Read 2 more answers
Find the solution of this system of two linear equations using substitution 11x+3y=103 and y =3x+1
Lesechka [4]
11x+3y=103 and y=3x+1. 

11x+3(3x+1)=103  -----> plug in (3x+1) for y in the first equation.  You will want to distribute the 3 to the 3x+1 to get something that looks like:

11x+9x+3=103    ------> now you want to combine like terms 

20x+3=103 ---> subtract 3 from both sides
20x=100   ----> divide both sides by 20
x=5    

y=3(5)+1     ---> I like to plug in this to the equation that already has y isolated.  3*5 is 15, add 1 and you find that y=16.

(5, 16) will be your final answer (:
8 0
3 years ago
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