Simplify the difference. (4w2 – 4w – 8) – (2w2 + 3w

Which of the following shows as a mixed number and as an improper fraction?

Marysya12 [62]

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6 0

3 years ago

Through: (2, 2), parallel to y = x +4

dexar [7]

Answer:

y = x

Step-by-step explanation:

We can use slope-point form.

(y-y1) = m(x-x1)

m is a slope. If the line is parallel than slopes are the same.

y = x + 4, for this line slope = 1, so for line we have to find slope is also 1.

(y-y1) = m(x-x1)

m=1, x1 = 2, y1 = 2

(y - 2) = 1(x-2)

y - 2 = x - 2

y = x

8 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago

At what rate per annum does the compound interest of Rs 576 becomes to Rs 153 in 2 years

ArbitrLikvidat [17]

Answer:

The value of rate per annum is R = 12.5 %

Step-by-step explanation:

Principal amount = 576

Interest = 153

Amount after 2 years = 576 + 153 = 729

We know that

$A = P [1 + \frac{R}{100} ] ^{T}$

Put all the values in above equation

$729 = 576 [1 + \frac{R}{100} ]^{2}$

$\frac{27}{24} = 1 + \frac{R}{100}$

R = 12.5 %

This is the value of rate per annum.

4 0

4 years ago

Hey! A step by step explanation on this would be great! Thanks!<br> (25 Points)

kicyunya [14]

Step-by-step explanation:

We find the stationary point of (20 + 2x)(1200 - 60x),

where x is the unit rate of increase/decrease.

d/dx [(20 + 2x)(1200 - 60x)]

= d/dx (-120x² + 1200x + 24000)

= -240x + 1200.

When d/dx [(20 + 2x)(1200 - 60x)] = 0,

We have -240x + 1200 = 0. => x = 5.

Price per shirt that maximise revenue

= $20 + $2x = $20 + $2(5) = $30.

Maximum revenue

= (20 + 2(5))(1200 - 60(5))

= $30 * 900 = $27,000.

6 0

3 years ago

Simplify the difference. (4w2 – 4w – 8) – (2w2 + 3w – 6)