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zaharov [31]
3 years ago
7

Can someone please help me with d, g and h because I can never seem to know how to find the domain and range.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
g)\ y=\cos x\to y^{-1}=\arccos x.\ The\ domain:\ [-1;\ 1].\\\\h)\ y=\cos x\to y^{-1}=\arccos x.\ The\ range:\ [0;\ \pi]
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Which of the following points is in the solution set of y > -x2 + 5? (0, 5) (1, 3) (2, 4)
mylen [45]

Answer:

(2, 4)

Step-by-step explanation:

The only point that satisfies the inequality is (2, 4).

(0, 5) : -0^2 +5 = 5 . . . . . not > 5

(1, 3) : -1^2 +5 = 4 . . . . . . 3 is not > 4

(2, 4) : -2^2 +5 = 1 . . . . . . 4 is greater than 1, so this point is in the solution set.

5 0
3 years ago
Help plz no wrong answers plz help me ASAP thanks!
wariber [46]

Answer:

480

Step-by-step explanation:

The probability she will roll 2 odd numbers is 12/50  (the number of odd rolls over the total).  This simplifies to 6/25

Multiply the probability times the total number of rolls to get a good estimate of the number of rolls that till be odd odd

6/25 * 2000 =480

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2064%2F4" id="TexFormula1" title="\sqrt{x} 64/4" alt="\sqrt{x} 64/4" align="abs
ozzi

Answer: =16\sqrt{x}

Step-by-step explanation:

\sqrt{x}\frac{64}{4}=16\sqrt{x}

8 0
2 years ago
How to find the perimeter of a right triangle
QveST [7]

Answer:

There are three primary methods used to find the perimeter of a right triangle.

1. When side lengths are given, add them together.

2. Solve for a missing side using the Pythagorean theorem.

3. If we know side-angle-side information, solve for the missing side using the Law of Cosines.

Step-by-step explanation:

there i hope this helps!!!

6 0
3 years ago
Given the following system of equations: −x + y = 2 2x + 4y = 32 What action was completed to create this new equivalent system
tiny-mole [99]

Answer:

you just need to devide by 2 the second equation

Step-by-step explanation:

  • -x + y = 2 (you leave it as it is)

  • 2x + 4y =32 => 2x/2 +4y/2 = 32/2

=> x + 2y =16

we can devide or multiply in an equation by any number we want, as long as we do it to every term.

6 0
3 years ago
Read 2 more answers
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