Answer:
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Step-by-step explanation:
I am joyous to assist you at any time.
Answer:
5km costs $4
if you take the intial charge of $2, you're paying $4 per 5km
hence 10km= 2 *5km= 2*$4=$8+initial charge $2= $10
15Km= 3*5km= 3*$4= $12 + intial charge $2 = $14
Step-by-step explanation:
Answer:
Step-by-step explanation:
First question 1 = 0.3 = 0.7
Second question 60/5=12 so 12 hours
Third question first find lcm so 6
2 3/6 and 7 2/6
2.5 + 2.5 = 5 so 2 cakes
Fourth question
729/14 um calculator but ok 729/14=52.07 so 52.1
You said you'd report me if i only did 3,2,or 11 but i did 4 so i think im fine
Answer:
50
Step-by-step explanation:
The value of x is 50 degrees
bcoz it is isosceles triangle
so two angles are equal
so value of x is 50
I hope this will help u
Answer:
Part c: Contained within the explanation
Part b: gcd(1200,560)=80
Part a: q=-6 r=1
Step-by-step explanation:
I will start with c and work my way up:
Part c:
Proof:
We want to shoe that bL=a+c for some integer L given:
bM=a for some integer M and bK=c for some integer K.
If a=bM and c=bK,
then a+c=bM+bK.
a+c=bM+bK
a+c=b(M+K) by factoring using distributive property
Now we have what we wanted to prove since integers are closed under addition. M+K is an integer since M and K are integers.
So L=M+K in bL=a+c.
We have shown b|(a+c) given b|a and b|c.
//
Part b:
We are going to use Euclidean's Algorithm.
Start with bigger number and see how much smaller number goes into it:
1200=2(560)+80
560=80(7)
This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.
Part a:
Find q and r such that:
-65=q(11)+r
We want to find q and r such that they satisfy the division algorithm.
r is suppose to be a positive integer less than 11.
So q=-6 gives:
-65=(-6)(11)+r
-65=-66+r
So r=1 since r=-65+66.
So q=-6 while r=1.
