Answer: Hope this helps you!
Edit: the 2nd photo is more in detail and should help you better. Good luck!
Step-by-step explanation:
X+y+z=2 5x+5y+5z=3 4x+y-3z=-6
1 answer:
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Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x =
x - 3 = 0; x = 3
the solutions are
Both values are real numbers, therefore correct option is b