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Taya2010 [7]
3 years ago
7

What is the answer for number six?

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0
I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0
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Suppose Ted, a sociologist, is interested in comparing the amount of time that husbands and wives in the United States each spen
lidiya [134]

Answer:

1. A matched-pairs t-test is valid, despite the sample being a small representation of the population, because the sample is a simple random sample and has a distribution with a single peak.

Step-by-step explanation:

The matched-pairs test is valid, for the reasons given in choice 1. Here's why:

  • We do have matched pairs, not a 2-sample t-test, because each two are paired by the house they live in. Husband and wife live together: it's safe to pair them. (This rules out option 5.)
  • Check conditions: The sample is large enough (fulfilling the <u>sample size condition)</u>. The sample data is fairly normal, although we don't know the population data, and the sample size is over 40, so we consider it a fairly large sample (fulfilling the <u>nearly normal condition)</u>. We don't know about outliers, but we'll have to assume Ted doesn't have any, because they aren't mentioned.
8 0
3 years ago
Use rounding or compatible numbers to estimate the difference 359-224
tiny-mole [99]
359 goes to 360
224 goes to 220
360-220=140
I moved the answer up one then down four the way I moved the original numbers, so 140 is actually down three of the actual answer which must be 143 then
6 0
3 years ago
10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sampl
Alex17521 [72]

Here is the full question:

The \  shell \   of  \ the \  land  \ snail \  Limocolaria  \ martensiana  \ has \  two  \ possible  \ colorforms:  \ streaked  \ and  \ pallid.  \ In  \  a \ certain \  population  \ of  \ these   \ snails,  \ 60\%  \ o f  \ theindividuals \  have  \ streaked  \ s hells.\ 16  \ Suppose  \ that  \ a  \ random \ sample  \ of \  10  \ snailsis \  to  \ be \ chosen  \ from  \ this \  population.  \ F ind  \ the  \ probabilit y \  that  \ the  \ percentage  \ of

streaked-shelled  \ snails   \ in  \ t he  \ sample \  will  \ be

(a) 50\%. \  (b) 60\%.  \ (c) 70\%.

Answer:

(a) 0.2007

(b) 0.2510

(c) 0.2150

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

X \sim Binom (n =1 0, p = 0.60)

The Probability mass function (X) is:

P(X =x)= (^n_x) p^x(1-p)^{n-x}; x = 0,1,2,3...

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ = \sqrt{np(1-p)}

= \sqrt{10*0.6*(1-0.6)}

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

a)

P(X = 0.5) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_5 * (0.6)^5(1-0.6)^{10-5}

= \dfrac{10!}{5!(10-5)!} * (0.6)^5(1-0.6)^{10-5}

= 0.2007

b)

P(X = 0.6) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_6 * (0.6)^6(1-0.6)^{10-6}

= \dfrac{10!}{6!(10-6)!} * (0.6)^6(1-0.6)^{10-6}

= 0.2510

c)

P(X = 0.7) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_7 * (0.6)^7(1-0.6)^{10-7}

= \dfrac{10!}{7!(10-7)!} * (0.6)^7(1-0.6)^{10-7}

= 0.2150

7 0
3 years ago
Suppose that there were a strong correlation between the variables n and a
DerKrebs [107]

Answer:

D

Step-by-step explanation:

correlation does not= causation

3 0
3 years ago
A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. Each
Ostrovityanka [42]

Answer:

There were 7 small boxes and 14 large boxes shipped.

Step-by-step explanation:

This problem may be solved by a system of equations:

I am going to say that:

x is the number of small boxes used

y is the number of large boxes used

There were twice as many large boxes shipped as small boxes shipped

This means that y = 2x

Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.

This means that 45x + 80y = 1435

So we have to solve the following system:

y = 2x

45x + 80y = 1435

45x + 80(2x) = 1435

205x = 1435

x = \frac{1435}{205}

x = 7

y = 2x = 2(7) = 14

There were 7 small boxes and 14 large boxes shipped.

7 0
3 years ago
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