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Taya2010 [7]
3 years ago
7

What is the answer for number six?

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0
I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0
You might be interested in
Write a quadratic function f whose zeros are 3 and -10.<br> f(x) =
andreyandreev [35.5K]

Answer:

f(x)= x^2 + 7x - 30

5 0
3 years ago
PLEASE!!!
ANEK [815]

9514 1404 393

Answer:

  1. 30m +50 = 20m +100
  2. m = 5
  3. yes. symmetric property of equality.

Step-by-step explanation:

1. The expression for c in the first equation is (30m+50). Substituting that for c in the equation ...

  c = 20m +100

gives you ...

  30m +50 = 20m +100

__

2. Adding -50-20m to both sides gives ...

  10m = 50

  m = 5 . . . . . . . divide by 10

__

3. Doing the substitution in reverse, you would substitute (20m+100) for c in the equation ...

  c = 30m +50

to get ...

  20m +100 = 30m +50

This is the equation of part 1 with the expressions swapped to the other side of the equal sign. The symmetric property of equality tells you that changing sides of the equal sign does not change the value of the variable(s).

You get the same solution.

3 0
3 years ago
Need help on number 2 plz I appreciate it thank you so much
vladimir1956 [14]

Answer:

\angle PQR, \angle SQR, and \angle PQS

Or

angle PQR, angle SQR and angle PQS

Step-by-step explanation:

The three different angles in the diagram are angle PQR, angle SQR and angle PQS.

Another way of writing this is using an angle sign before the alphabets follows. Thus:

\angle PQR, \angle SQR, and \angle PQS

6 0
3 years ago
What is the equation for the line? enter your answer in the box
Igoryamba
To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)

The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept

First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c

Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4

Based on the above calculations, the equation of the line is:
y = -2x - 4
7 0
3 years ago
Plsss helppp I’m dying!! —&gt; Complete the square to determine if the equation is a circle, quadratic equation, or other
sashaice [31]

a) The equation represents an ellipse.

b) The equation represents a circle.

c) The equation represents a parabola.

<h3>How to infer the graphical form of a general equation</h3>

In this problem we have <em>general</em> equations of the form A · x² + B · y² + C · x + D · y + E = 0, which have to be modified into <em>standard</em> form to infer its <em>graphical</em> form. This procedure can be done by <em>algebra</em> properties:

16 · x² + 4 · y² + 96 · x - 8 · y + 84 = 0

[(4 · x)² + 2 · 12 · (4 · x)] + [(2 · y)² - 2 · 2 · (2 · y)] = - 84

[(4 · x)² + 2 · 12 · (4 · x) + 144] + [(2 · y)² - 2 · 2 · (2 · y) + 4] = 64

(4 · x + 12)² + (2 · y + 2)² = 64

4² · (x + 3)² + 2² · (y + 2)² = 64

(x + 3)² / 4 + (y + 2)² / 16 = 1 : Ellipse

x² + y² + 8 · x - 6 · y - 15 = 0

(x² + 8 · x) + (y² - 6 · y) = 15

(x² + 2 · 4 · x + 16) + (y² - 2 · 3 · y + 9) = 40

(x + 4)² + (y - 3)² = 40 : Circle

x² + 6 · x + 4 · y + 5 = 0

x² + 6 · x + 5 = - 4 · y

y = - (1 / 4) · x² - (3 / 2) · x - (5 / 4) : Parabola

To learn more on ellipses: brainly.com/question/19507943

#SPJ1

4 0
1 year ago
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