W- (3,4)
Z- (-1,1)
X-(-1,-3)
Y-(-4,1)
The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
<h3>How to determine the number of ways</h3>
Given the word:
ESTABROK
Then n = 8
p = 6
The formula for permutation without restrictions
P = n! ( n - p + 1)!
P = 8! ( 8 - 6 + 1) !
P = 8! (8 - 7)!
P = 8! (1)!
P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1
P = 40, 320 ways
Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
Learn more about permutation here:
brainly.com/question/4658834
#SPJ1
Answer: Undefined
Step-by-step explanation:
4y+x=12, 2x=24-8y
Isolate x by subtracting 4y
4y+x=12
x=12-4y
Plug the equation for x in to anywhere you see the variable x in the other equation
2(12-4y)=24-8y
Distribute 2
24-8y=24-8y
Get the variables on one side so add 8y (cancels out)
24=24
Can’t solve its undefined
Step-by-step explanation:
5.4×-0.9=n
n=-4.86
(-4/5)/(1/3)=x
X=-2 2/5
