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hammer [34]
3 years ago
11

Is the difference between two negative numbers numbers is always negative.

Mathematics
1 answer:
Lorico [155]3 years ago
4 0
Yes. Think of it like this. You borrowed $1 from your friend for a candy bar. You now have -$1 because you owe your friend money. If you ask your friend for another $5 because you found another thing you wanted you have -$6. When you already have a negative, you are subtracting even more from that, which brings you to an even higher negative number
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The mean of 9, 6, 5, 64, 7, 4, 2
Georgia [21]

Answer:

The mean is 11.25

Step-by-step explanation:

to get the mean youll first add all the numbers together and divide them by the amount of numbers that you have then you get your avarage. Once you have your avarage then you subtract it from all your numbers , add up what you get and divide again by the amont of numbers you have

4 0
4 years ago
Read 2 more answers
C gives the cost, in dollars, of a cafeteria meal plan as a function of the number of meals
SVETLANKA909090 [29]

Answer:

9

Step-by-step explanation:

First, write the equation.

C(n) = 4 + 3n

We know that C(n) = 31, so we can substitute it.

31 = 4 + 3n

Subtract 4 from both sides to isolate the term with the variable.

27 = 3n

Divide both sides by 3 to get the variable by itself.

9 = n

4 0
3 years ago
Read 2 more answers
Diego is solving the inequality 100 − 3x ≥ -50. He solves the equation 100 − 3x = -50 and gets x = 50. What is the solution to t
ZanzabumX [31]

Answer:

x≤50

Step-by-step explanation:

100-3x≥-50

subtracting 100 at both side on inequality

-100+100-3x≥--50-100

-3x≥-150

Dividing both sides by 3

-3x/3≥-150/3

-x≥--50

Adding 50 on both sides

-x+50≥-50+50

-x+50≥0

Adding x on both sides

-x+x+50≥0+x

50≥x

so,

x≤50

7 0
3 years ago
Read 2 more answers
Why are there two solutions for the equation |6 + y| = 2? Explain.
GaryK [48]

Solution, \left|6+y\right|=2\quad :\quad y=-8\quad \mathrm{or}\quad \:y=-4

Steps:

|f\left(y\right)|=a\quad \Rightarrow \:f\left(y\right)=-a\quad \mathrm{or}\quad \:f\left(y\right)=a, 6+y=-2\quad \quad \mathrm{or}\quad \:\quad \:6+y=2

6+y=-2\quad :\quad y=-8,\\6+y=-2,\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}, 6+y-6=-2-6,\\\mathrm{Simplify}, y=-8

6+y=2\quad :\quad y=-4,\\6+y=2,\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides},6+y-6=2-6\\\mathrm{Simplify},y=-4

\mathrm{Combine\:the\:ranges}, y=-8\quad \mathrm{or}\quad \:y=-4

\mathrm{The\:Correct\:Answer\:is\:Because\:of\:the\:absolute\:value,\:It\:could\:be\:Positive\:or\:negative.}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

7 0
4 years ago
I have 2 questions, they're similar, but i have no idea. can someone please help me.
Dimas [21]

Answer:

First Picture:

\sqrt{x} -3=3-\sqrt{x}\\\\\x-3=0\\  +3  +3\\x=3

Second Picture:

2/3(9x-6)-4=9x-6

(6x-4-4=9x-6\\6x-8=9x-6\\   -9        -9\\\\-3x-8=-6\\      \\+8  +8\\-3x=2\\\\x=-2/3

5 0
3 years ago
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