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coldgirl [10]
3 years ago
12

4

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0
The time needed to complete a hole in golf 81.25
kiruha [24]3 years ago
3 0

Answer:

Step-by-step explanation:

If 4 hole need to complete in 25 minutes than 1 hole need to fine in how many minute

Than 25÷4=6.25 one hole

6.25×13= 81.25

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How to answer these questions?
MariettaO [177]
I think you put each set of data in to l1 and l2 on your calculator nd find the linear regression ( r value) and you can get to the r value by going to stat diagnostic on
7 0
3 years ago
The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0
2 years ago
Find the difference.<br> -7-(-5)
Dvinal [7]

Answer:

Remember: minus a minus is a plus:

=11

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Factor (16a2 - 49) completely
riadik2000 [5.3K]

Answer:

(4a+7)(4a-7)

Step-by-step explanation:

5 0
3 years ago
(7 x 10^−12)(4 x 10^5) in scientific notation
Radda [10]
<span>(7 x 10^−12)(4 x 10^5)
= (7x4) x 10^-7
= 28 x 10^-7
= 2.8 x 10^-6</span>
3 0
3 years ago
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