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vodka [1.7K]
3 years ago
11

Evaluate 3x-6y if x=2 and y=0

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

3×2-6×0

6-0

6 is the answer pls mark as brainliest

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jason earns 15 dollars an hour at his job he spends 40 a day create an exprssion to desribe his savings in one day where x is th
geniusboy [140]

Answer:

Let y be the total earns of jason

where x is the number of hours jason works that day

y=15x ×40

y=600x

total earns of jason y = 600x



7 0
3 years ago
PLEASE PLEASE HELP ME! thank you so so much
viva [34]

Answer:

6π

Step-by-step explanation:

(135/360)×π×4²

(135/360)×π×16

=6π

6 0
3 years ago
The area of a square is 15.1 units². Estimate the length of the sides. Explain how you estimated.
kykrilka [37]

If it is just an estimate then it would be around <em>4</em>. 15.1 is pretty close to 16 which has a perfect square root of 4. Since it is a square both length and width would be the same. To check it you can just square 4 or 4 times 4 and get 16. Hopefully I helped! And sorry if I am wrong.

BTW the exact answer would be 3.88~ (square root of 15.1) just incase you needed that. :)

6 0
3 years ago
A small airplane can fly 12 miles in 3 minutes. At this rate, how far can it fly in 7 minutes? In an hour?
Kay [80]

Answer:

28 miles in 7 minutes, 240 miles in an hour

Step-by-step explanation:

We can first simplify the rate to miles per minute. Since the plane goes 12 miles in 3 minutes, we can divide it by 3 to find how much it travels in one minute. 12 divided by 3 is 4 and 3 divided by 3 is 1

The plane travels 4 miles a minute

To find how much it travels in 7 minutes, multiply by 7

4x7 is 28

28 miles in 7 minutes

To find an hour, multiply by 60

4x60= 240

240 miles in an hour

7 0
3 years ago
Find the taylor polynomial t3(x) for the function f centered at the number
inysia [295]

Answer:

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

Step-by-step explanation:

We are given that

f(x)=7tan^{-1}(x)

a=1

T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}

Substitute n=3 and a=1

t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}

f(x)=7tan^{-1}(x)

f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}

Where tan^{-1}(1)=\frac{\pi}{4}

f'(x)=\frac{7}{1+x^2}

Using the formula

\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}

f'(1)=\frac{7}{2}

f''(x)=\frac{-14x}{(1+x^2)^2}

f''(1)=-\frac{7}{2}

f''(x)=-14x(x^2+1)^{-2}

f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})

By using the formula

(uv)'=u'v+v'u

f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}

f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}

f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}

Substitute the values

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

7 0
3 years ago
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