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Leviafan [203]
3 years ago
8

What is 6(c-4) > 18

Mathematics
2 answers:
amid [387]3 years ago
6 0
I believe it would be c>7
tigry1 [53]3 years ago
5 0
C><span>7 is your answer. Hope this helps :)</span>
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What function is represented below?
Paladinen [302]
By graphing the given options as shown in attached figure
<span>f(x) = (1/4)^x+2   ⇒⇒⇒⇒ The black graph
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</span> f(x) = (1/4)^x-2    <span><span>⇒⇒⇒⇒ The blue graph
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The correct answer will be the blue graph

f(x) =   (\frac{1}{4})^{(x-2)}



4 0
3 years ago
Read 2 more answers
Help I’ll mark brainliest
Thepotemich [5.8K]

Answer:

The 2nd one.

Step-by-step explanation:

6 0
3 years ago
Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

5 0
3 years ago
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