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3 years ago

Ronnie receives $40 for his birthday. Then he spends $15 at the moives

Mathematics

1 answer:

kobusy [5.1K]3 years ago

5 0

Answer = 25

On his birthday he gets $40. Then he spends $15

Subtract 15 from 40 which gives you 25

40-15=25

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X^2-8x+16 divided by ax-4x numerator

Vedmedyk [2.9K]

Answer:

Given:

1). $x^2-8x+16$ divided by $x-4$

⇒ $\frac{x^2-8x+16}{x-4}$

⇒ $\frac{x^2-2\times x\times 4+4^2}{x-4}$

By factorising numerator by using identity, $(a-b)^2=a^2-2\times a \times b +b^2$

⇒ $\frac{(x-4)^2}{x-4}$

⇒ $\frac{(x-4)\times(x-4)}{x-4}$

⇒ $x-4$ <u> {Answer}</u>

2). $3x^2y$ divided by $6xy^2$

⇒ $\frac{3x^2y}{6xy^2}$

⇒ $\frac{3\times x\times x\times y}{6\times x\times y\times y}$

⇒ <u> $\frac{x}{2y}$ </u> <u>{ Answer}</u>

4 0

3 years ago

Kaci bought a birthday cake like the one shown below. If a=5inches,b=5inches,c=10 inches, and d=3inches what is the volume of th

Gnom [1K]

Answer:

75+150=225 in^2

Step-by-step explanation:

Separate each layer.

Area1+Area2= Total area

A1= a*b*d

A2=a*c*d

A1=5*5*3=75 in^2

A2=5*10*3=150 in^2

75+150=225 in^2

7 0

2 years ago

A local business has an area reserved behind the store for a parking lot that is 78 meters long by 19 meters wide. The stalls of

S_A_V [24]

The total area available for cars to park will be 858m².

<h3>How to calculate the area?</h3>

The area of the parking lot will be:

= 78 × 19

= 1482m²

The area of aisle will be:

= 8 × 78

= 624m²

The available area will be:

= 1482m² - 624m²

= 858m².

The compact parking spaces that will fit in the lot will be:

N × 12.5 = 858

N = 858/12.5

N = 68

The non compact parking spaces that will fit in the lot will be:

N × 16.5 = 858

N = 858/16.5

N = 52

Learn more about area on:

brainly.com/question/7438648

#SPJ1

5 0

1 year ago

When planning for a party, one caterer recommends the amount of meat be at least 2 pounds less than 1/3 the total number of gues

ehidna [41]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x-----> the total number of guests

y -----> the amount of meat

we know that

The inequality that represent this situation is equal to

$y\geq \frac{1}{3}x-2$

Note The inequality is "greater than or equal" because the given statement say "at least"

The solution of this inequality is the shaded area above the solid line $y=\frac{1}{3}x-2$

The slope of the solid line is positive

The y-intercept of the solid line is -2

The x-intercept of the solid line is 6

therefore

The graph in the attached figure

Remember that

The values of x an y cannot be a negative number

5 0

3 years ago

Read 2 more answers

PLEASE HELP!!

Len [333]

C, 125. Hope I helped.
btw, u gotta do 35+30+25+20+15

7 0

3 years ago

Read 2 more answers