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rewona [7]
3 years ago
10

Find the value of x that makes u 11 v. 7x + 14 8x + 6 X =

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

The X=2 because X+X=2

Step-by-step explanation:

So,the answer is 2

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Need help............
svp [43]

Answer:

i would say C

Step-by-step explanation:

6 0
3 years ago
6th grade math, help pleasee:)
Debora [2.8K]

Answer:

1/5 cup

Step-by-step explanation:

Sugar: water

1             5

We want 1 cup water, so divide each side by 5

1/5 :  5/5

1/5 : 1

There is 1/5 cup sugar to 1 cup water

4 0
3 years ago
Read 2 more answers
A gardener already has four and one over 2 ft of fencing in his garage. He wants to fence in a square garden for his flowers. Th
NikAS [45]
<h2>Answer:</h2>

6\frac{1}{2}<u>, "six and one over two ft".</u>

<h2>Step-by-step explanation:</h2>

Let's considerate the fact that the garden has a <u>square shape</u>.

<h3>1. Finding values of interest.</h3>

Amount of fence that the gardener already has: 4\frac{1}{2} ft.

Length of one side: 2\frac{3}{4} ft.

If one side measures 2\frac{3}{4} ft, and the square garden has 4 sides of equal length, because it's a square, then we must multiply the measure of one side by 4 to find the total length of fence needed:

4*(2\frac{3}{4})=\\ \\4*(2+\frac{3}{4})=\\ \\(4*2)+(4*\frac{3}{4})=\\ \\8+(\frac{12}{4} )=\\ \\8+3=\\ \\11

<h3>2. How much more does he need?</h3>

The gardener already has  4\frac{1}{2} , which equals 4 + \frac{1}{2}. Hence, the difference between the amount needed and the amount that the gardeneralready has will give us the remaining amount required. Let's do that:

11-(4+\frac{1}{2} )=\\ \\11-(\frac{8}{2} +\frac{1}{2} )=\\ \\11-\frac{9}{2}= \\ \\\frac{22}{2} -\frac{9}{2}=\\\\ \frac{13}{2}

<h3>3. Express your result.</h3>

\frac{13}{2} =\\ \\\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{1}{2}= \\ \\6+\frac{1}{2}=\\ \\6\frac{1}{2}

8 0
2 years ago
1. Find the measure of the side indicated (x). Round to the nearest tenth. Show your work to support your
lidiya [134]

Answer:

Is this for a Trig class?  just wondering

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

we want to find the Hypotenuse (Hyp)  and are given an angle and the adjacent side (adj)  sooo use  CAH  , b/c it has all of the pieces

Cos(37) = Adj / Hyp

Cos(37) = 11 / Hyp

swap  Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra

Hyp = 11 / Cos(37)

now solve with your handy TI 83 / 84 / 89   calculator :)  if you don't have one go get one . :D get the 89 if  you are going into engineering classes...  the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )

Hyp = 13.77349...

Hyp = 13.8 ( rounded to nearest 10th )  :)

3 0
3 years ago
Observe os pontos Z, Y, W, X e V marcados na reta numérica abaixo.
adelina 88 [10]

Y

A raiz quadrada de 14 seria 3.74165738677 ou 3.7

Arredondamos para 4 já q 7 é próximo de 10

5 0
3 years ago
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