By Stokes' theorem, the line integral of over
is given by the surface integral of the curl of
over
, where
is the region of intersection of the plane
and the cylinder
with
having positive/upward orientation.
Parameterize by
with and
.
Take the normal vector to to be
The curl of is
Then the line integral is equivalent to
Answer:
For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)
The transformation to rectangular coordinates is written as:
x = R*cos(θ)
y = R*sin(θ)
Here we are in the unit circle, so we have a radius equal to 1, so R = 1.
Then the exact coordinates of the point are:
(cos(θ), sin(θ))
2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.
Remember that:
tan(x) = sin(x)/cos(x)
So if sin(x) = 0, then:
tan(x) = sin(x)/cos(x) = 0/cos(x) = 0
So tan(x) is 0 in the points such that the sine function is zero.
These values are:
sin(0°) = 0
sin(180°) = 0
Then the two possible points where the tangent is zero are the ones drawn in the image below.
Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.
If the coordinates of the top of the triangle (breadth) is (−5,6) and (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:
D = √(y₂-y₁)²+(x₂-x₁)²
Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6
D = √(6-6)²+(-2-(-5))²
D = √0²+3²
D = √9
D = 3 units
Breadth = 3 units
Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.
16 = 2(3+L)
16 = 6+2L
16-6 = 2L
2L = 10
L = 10/2
L = 5 units.
<em>Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.</em>
