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photoshop1234 [79]
3 years ago
5

70 PTS HELP PLS!!!!!

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

28*4/7

Step-by-step explanation:

4/7

   the 7 represents the 28.  28 is a multiple of 7.

<u>28</u>  *   <u>4</u>   =     <u>112</u>   =   16

 1        7           7

<u><em>there are 16 girls</em></u>

also we know 4*7=28 so if we count the multiples of 4, there is 4 8 12 and the 4th multiple is 16.

<u><em /></u>

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a) df=n-1=16-1=15

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c) df=n-1=26-1=25

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Since is a one-side upper test the p value would be:      

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So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation      

\bar X represent the sample mean

s represent the standard deviation for the sample

n sample size      

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:      

Null hypothesis:\mu \leq 20      

Alternative hypothesis:\mu > 20      

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

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(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=16-1=15

The statistic calculated is given by t=3.3  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>3.3)=0.0024  

So since the p value is lower than the significance level pv we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:  

df=n-1=8-1=7

The statistic calculated is given by t=1.8  

Since is a one-side upper test the p value would be:      

p_v =P(t_{7}>1.8)=0.057  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

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df=n-1=26-1=25

The statistic calculated is given by t=-0.6  

Since is a one-side upper test the p value would be:      

p_v =P(t_{25}>-0.6)=0.723  

So since the p value is higher than the significance level pv>\alpha we FAIL to reject the null hypothesis.

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168 h = [?] days helppp
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