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3 years ago

a man who is 6 feet tall cats a shadow that is 15 feet long.A tree casts a similar shadow is 22 FT how tall is the tree?

2 answers:

7 0

The tree might be 13ft tall because what I did was that I subtracted 15 from 22 and then got 7. Adding this 7 to the 6 to get 13ft.

Hope this helps. Sorry if wrong.

Debora [2.8K]3 years ago

3 0

Hello There

Answer: 13

Here are the steps:
First we subtract 15 from 22 and then got 7

15 - 22 = 7

Finally we Add 7 + 6 = 13

Which is our final answer

I hope I helped
-Chris.

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Is 3/8 bigger than 4/10

Zigmanuir [339]

Answer:

no 4/10 is bigger than 3/8

Step-by-step explanation:

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Solve the equation for all values of x. (x + 3)(72 – 9) = 0

Alenkasestr [34]

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x has to be -3 for the answer to be 0

Step-by-step explanation:

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3 years ago

Read 2 more answers

A restaurant with two locations buys twelve bags of flour and eight large bags of sugar. Location A receives seven bags of flour

Alborosie

You want to solve this set of linear equations by the elimination method.

Let x=price of bag of flour and y=price of bag of sugar

Multiply the first equation by -3.

-3(7x+5y=584)
Multiply the second equation by 5.
5(5x+3y=384)

Solve by elimination.

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Substitute value of x into one of the original equations.

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3 years ago

Solve the system of linear equations by substitution. 2x-y=3 x+5y=14

Arturiano [62]

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

-10y - y=3 - 28

-11y= -25

divide both sides by coefficient of y

-11y/-11 = -25/-11

y= 25/11

Substitute y= 25/11 in equation 3

x=14 - 5(25/11)

x= 14 - 125/11

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3 years ago

Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L 18, start fraction, start text, L, end text, divided

Fiesta28 [93]

Answer:

Uche's pumping rate is 300 mL/s.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

1 L/min = 16.6667 mL/s.

18 L/min = 16.6667 × 18 mL/s.

18L/min = 300 mL/s.

Therefore, Uche's pumping rate is 300 mL/s.

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3 years ago