Answer:
512 ways
Step-by-step explanation:
Given
Selection
Faculty Member = 1
Male Student = 1
Female Student = 1
Parent = 1
School Board Member = 1
Select from:
Faculty Member = 2
Male Student = 4
Female Student = 4
Parent = 4
School Board Member = 4
Required
Determine how many ways they can be selected
There are 2 faculty members of which 1 will be selected from.
Any of these two members may be selected.
So, Selection = 2
There are 4 male students of which 1 will be selected from.
Any of these four students may be selected.
So, Selection = 4
There are 4 female students of which 1 will be selected from.
Any of these four students may be selected.
So, Selection = 4
There are 4 parents of which 1 will be selected from.
Any of these four parents may be selected.
So, Selection = 4
There are 4 school board members of which 1 will be selected from.
Any of these four members may be selected.
So, Selection = 4
Total number of selection is then calculated as thus:
<em>Hence, there are 512 ways</em>
The second. 4(8) it should be 32. not 48.
Answer:
-4 + -6 = -10
Step-by-step explanation:
you just have to start at the negative four and count up to the number negative ten, then you think “how many spaces are there between four and ten? SIX. so you just take six and turn it negative, boom.
If you are solving by substituting A=50 and B=75