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zimovet [89]
3 years ago
9

Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on t

he expected date of ripening. During a certain week, the data to the right were recorded at a fruit delivery station. Complete parts (a) through (d) below.
34 trucks went out carrying early peaches;

65 carried late peaches;

65 carried extra late peaches;

22 carried early and late;

34 carried late and extra late;

13 carried early and extra late;

6 carried all 3

8 carried only figs (no peaches at all)

a) how many trucks carried only late peaches? B) how many carried only extra late? c) how many carried only one type of peach? d) how many went out total?

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

a) 12

b) 18

c) 37

d) 97

Step-by-step explanation:

Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on the expected date of ripening. During a certain week, the following data were recorded at a fruit delivery station:

34 trucks went out carrying early peaches ;

61 carried late peaches ;

50 carried extra late;

25 carried early and late;

30 carried late and extra late;

8 carried early and extra late;

6 carried all three;

9 carried only figs (no peaches at all) .

<u>To solve this problem, the best solution is to drawn a Venn Diagram, which is attached.</u>

(a) How many trucks carried only late variety peaches?

12

(b) How many carried only extra late?

18

(c) How many carried only one type of peach ?

7+12+18 = 37

(d) How many trucks (in all) went out during the week?

Sum of all the numbers on the Diagram:

7+2+6+19+12+24+18+9= 97

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